Chemistry Equilibrium MDCAT 2016
PMDC Verified Question 89 of 102
Value of \( K_{sp} \) for \( \text{PbSO}_4 \) system at \( 25^{\circ}\text{C} \) is equal to:
A
\( 1.6 \times 10^{-5} \text{ mol}^2 \text{dm}^{-6} \)
B
\( 1.6 \times 10^{-8} \text{ mol}^2 \text{dm}^{-6} \)
C
\( 1.6 \times 10^{-6} \text{ mol}^2 \text{dm}^{-6} \)
D
\( 1.6 \times 10^{-7} \text{ mol}^2 \text{dm}^{-6} \)
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option B: \( 1.6 \times 10^{-8} \text{ mol}^2 \text{dm}^{-6} \)
Concept:

This is a memory-based fundamental constant for the sparingly soluble salt Lead(II) sulfate at standard room temperature.

Formula:

$$ K_{sp}(\text{PbSO}_4) = 1.6 \times 10^{-8} \text{ at } 25^{\circ}\text{C} $$

Solution:

  • The dissociation is \( \text{PbSO}_{4(s)} \rightleftharpoons \text{Pb}^{2+} + \text{SO}_4^{2-} \).


  • Experimental data establishes its solubility product exactly at \( 1.6 \times 10^{-8} \text{ mol}^2 \text{dm}^{-6} \).


Why other options are incorrect:

These are incorrect magnitude variations of the standard accepted literature value.

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