Chemistry Equilibrium ETEA 2016
PMDC Verified Question 90 of 102
\( K_p = K_c(RT) \) in the equation if \( \Delta n < 0 \) then:
A
\( K_p = K_c \)
B
\( K_p < K_c \)
C
\( K_p > K_c \)
D
\( K_p < 0 \)
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option B: \( K_p < K_c \)
Concept:

The mathematical relationship between \( K_p \) and \( K_c \) depends heavily on the sign of \( \Delta n \) (change in gas moles).

Formula:

$$ K_p = K_c (RT)^{\Delta n} $$

Solution:

  • If \( \Delta n < 0 \) (negative), the term \( (RT)^{\Delta n} \) becomes a fraction \( \frac{1}{(RT)^{|\Delta n|}} \).


  • Assuming \( RT > 1 \) (which is true for standard thermodynamic temperatures in Kelvins), multiplying \( K_c \) by a fraction less than 1 yields a smaller number.


  • Therefore, \( K_p \) will be less than \( K_c \).


Why other options are incorrect:

\( K_p = K_c \) requires \( \Delta n = 0 \). \( K_p > K_c \) requires \( \Delta n > 0 \). Equilibrium constants cannot be negative (eliminating D).

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