Chemistry Gases UHS 2022
PMDC Verified Question 32 of 65
A gaseous mixture contains 9.6% \( \text{NH}_3 \), 22.6% \( \text{N}_2 \) and 67.8% \( \text{H}_2 \) gases. If the total pressure is 50atm, then the partial pressure of \( \text{H}_2 \) is:
A
67.8 × 100/50
B
50 × 100/100
C
67.8 × 50/100
D
67.8 + 50/100
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option C: 67.8 × 50/100
Concept:

According to Dalton's Law of Partial Pressures, the partial pressure of an individual gas in a mixture is equal to its mole fraction (or volume percentage in an ideal mixture) multiplied by the total pressure.

Formula:

$$ P_{gas} = \left(\frac{\% \text{ of gas}}{100}\right) \times P_{total} $$

Solution:

  • We are given the volume percentage of \( \text{H}_2 \) gas as 67.8%.


  • To find its mole fraction, we divide by 100: \( \frac{67.8}{100} \).


  • The total pressure \( (P_{total}) \) of the mixture is 50 atm.


  • Therefore, the partial pressure of \( \text{H}_2 \) is \( \frac{67.8}{100} \times 50 \), which matches the expression \( 67.8 \times \frac{50}{100} \).


Why other options are incorrect:

  • Option A: This formula incorrectly divides 100 by the total pressure, which breaks the mathematical definition of partial pressure.
  • Option B: This ignores the specific percentage of Hydrogen gas entirely.
  • Option D: Adding percentages and pressures is algebraically invalid in this context.

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