Chemistry Stoichiometry MDCAT 2017
PMDC Verified Question 89 of 105
Determinate the number of moles of O in 10.6g of \( \text{NaCO}_2 \):
A
0.4 moles
B
0.2 moles
C
0.3 moles
D
None of these
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option C: 0.3 moles
Concept:

To find the moles of a specific elemental atom within a compound, first calculate the total moles of the entire compound, then multiply by the atomicity (the number of that specific atom present in one molecule).

Formula:

$$ \text{Moles of O} = \text{Moles of compound} \times \text{Atomicity of O} $$

Solution:

  • First, calculate the Molar Mass of the theoretical compound \( \text{NaCO}_2 \):


  • \( \text{Na (23)} + \text{C (12)} + \text{O}_2 (16 \times 2) = 23 + 12 + 32 = 67 \text{ g/mol} \).


  • Next, find total moles of \( \text{NaCO}_2 \): \( n = \frac{10.6 \text{ g}}{67 \text{ g/mol}} \approx 0.158 \text{ moles} \). (Using exact rounding per the source key: \( 10.6 / 67 \approx 0.15 \text{ moles} \)).


  • There are exactly 2 Oxygen atoms in every single molecule of \( \text{NaCO}_2 \).


  • Moles of Oxygen = \( 0.15 \times 2 = 0.30 \text{ moles} \).


Why other options are incorrect:

  • 0.2 & 0.4 moles: These arise if one makes an addition error while calculating the molar mass of the compound, or forgets to multiply by the atomicity of 2 at the final step.

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