Chemistry Stoichiometry MDCAT 2017
PMDC Verified Question 88 of 105
Choose the correct option regarding number of particles associated with one mole of a substance:
A
\( 6.03 \times 10^{23} \)
B
\( 6.02 \times 10^{-23} \)
C
\( 6.01 \times 10^{-19} \)
D
\( 6.02 \times 10^{23} \)
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option D: \( 6.02 \times 10^{23} \)
Concept:

The mole is the SI base unit used to measure the amount of a substance. By rigid scientific definition, one mole of any substance contains exactly Avogadro's number of fundamental particles.

Formula:

$$ N_A = 6.022 \times 10^{23} \text{ mol}^{-1} $$

Solution:

  • Avogadro's constant, denoted by \( N_A \), is a universally established physical constant.


  • Its accepted value for most general chemistry calculations is rounded to \( 6.02 \times 10^{23} \).


  • This implies that 1 mole of carbon atoms contains \( 6.02 \times 10^{23} \) atoms, and 1 mole of water contains \( 6.02 \times 10^{23} \) molecules.


Why other options are incorrect:

  • \( 6.03 \times 10^{23} \): The decimal portion is inaccurate.


  • \( 6.02 \times 10^{-23} \): The exponent is negative, which implies a fraction of a single particle, which is impossible.


  • \( 6.01 \times 10^{-19} \): Completely wrong value and exponent.

Quality & Fidelity Assurance: Every question on BeambePrep is rigorously curated against the official PMDC syllabus with zero filler, zero out-of-syllabus content, and zero typos. When an authentic past paper originally contained a historical mistake or ambiguity from the examining board (such as UHS or NUMS), BeambePrep faithfully reflects the original paper while detailing the nuance and scientific consensus in the autopsy above.

Want to solve full-length papers under timed exam conditions?

Practice with zero-scroll lockdown sprints, dynamic latency zone timers, live peer selection telemetry, and the automated Amber mistake recovery loop.