Chemistry Transition Elements MDCAT 2015
PMDC Verified Question 59 of 68
Electronic configuration of Gold \([Au_{79}]\) is
A
\( [Xe] \; 4f^{14} , 5d^{10} , 6s^{1} \)
B
\( [Xe] \; 4f^{14} , 5d^{9} , 6s^{2} \)
C
\( [Xe] \; 4f^{10} , 5d^{10} , 6s^{2} \)
D
\( [Xe] \; 4f^{14} , 5d^{10} , 6s^{2} \)
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option A: \( [Xe] \; 4f^{14} , 5d^{10} , 6s^{1} \)
Concept:

Gold (\(Au\)) is in Group 11, similar to Copper and Silver. Elements in this group exhibit anomalous electron configurations to achieve a highly stable, fully filled \(d\)-subshell.

Solution:

  • Gold has an atomic number \(Z = 79\). The core is Xenon (\(Z = 54\)).


  • The \(4f\) subshell fills completely with 14 electrons: \(54 + 14 = 68\).


  • There are 11 valence electrons left for the \(5d\) and \(6s\) orbitals.


  • Instead of the expected \(6s^2 \; 5d^9\), one electron shifts from \(6s\) to \(5d\) to achieve the extra stability of a completely filled \(d\)-subshell (\(d^{10}\)).


  • The final configuration is \([Xe] \; 4f^{14} \; 5d^{10} \; 6s^1\).


Why other options are incorrect:

  • Option B represents the expected but incorrect \(d^9\) configuration.


  • Option D exceeds the total electron count (80 electrons instead of 79).

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