Chemistry Transition Elements MDCAT 2016
PMDC Verified Question 58 of 68
Which element of 3-d series of periodic table shows the electronic configuration of \(3d^{8} , 4s^{2}\)?
A
Copper
B
Zinc
C
Cobalt
D
Nickel
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option D: Nickel
Concept:

The atomic number can be determined by adding the number of core electrons to the valence electrons shown in the configuration.

Solution:

  • The configuration provided is \([Ar] \; 3d^8 \; 4s^2\).


  • Argon core (\(Ar\)) = 18 electrons.


  • Valence electrons = \(8 + 2 = 10\) electrons.


  • Total atomic number (\(Z\)) = \(18 + 10 = 28\).


  • Looking at the 3d transition series, atomic number 28 corresponds to Nickel (Ni).


Why other options are incorrect:

  • Copper is \(Z=29\) (\(3d^{10} \; 4s^1\)).


  • Zinc is \(Z=30\) (\(3d^{10} \; 4s^2\)).


  • Cobalt is \(Z=27\) (\(3d^7 \; 4s^2\)).

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