Logical Reasoning 11 Solved Past Papers 2022 to 2025 Archives

Set Theory, Integer Bounds & Arithmetic Past Papers

Solved past paper MCQs for Set Theory, Integer Bounds & Arithmetic from official UHS, NUMS, SZABMU, DUHS, and KMU examinations. Includes verified distractor autopsies and step-by-step cognitive explanations.

Boards Included: BUMHS DUHS NUMS SZABMU UHS
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Download Solved Set Theory, Integer Bounds & Arithmetic Past Papers (Print Edition)

Official printable A4 booklet containing all 11 verified past paper MCQs with unbroken options, 5-column rapid answer key, and Propolis cognitive error autopsies.

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#1 of 11 BUMHS 2025
Permalink
What would be the result of: \(10 - 3 \times 2\)?
A
4
B
6
C
14
D
17
View Answer & Propolis Autopsy
Correct Key: Option A Diagnostic Explanation
Concept: Arithmetic Order of Operations (BODMAS/PEMDAS).

Formula: Perform multiplication before subtraction.

Solution:

  • First multiply: \(3 \times 2 = 6\)


  • Then subtract: \(10 - 6 = 4\)


Why other options are incorrect:

• Option C: Incorrectly performs subtraction first: \((10 - 3) \times 2 = 14\).
#2 of 11 SZABMU 2025
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Every alphabet in the word "SURGEON" represents a fixed numerical value and the numbers when added, sum up to 99. Based on this, what will be the sum of the word "EORGNSU"?
A
102
B
78
C
99
D
56
View Answer & Propolis Autopsy
Correct Key: Option C Diagnostic Explanation
Concept: Anagram Numerical Equivalence.

Formula: \(\sum \text{Letter values} = \text{Constant}\)

Solution: "EORGNSU" is an anagram containing the exact same set of letters as "SURGEON". Since each letter's numerical value is fixed, the total sum remains unchanged at 99.

Why other options are incorrect:

• Options A, B, and D: Arbitrary numbers that ignore the principle of algebraic addition of identical variables.
#3 of 11 NUMS 2025
Permalink
Every alphabet in the word "SURGEON" represent a fixed numerical value and the numbers when added, sum up to 99. Based on this, what will be the sum of the word "EORGNSU".
A
102
B
78
C
99
D
56
View Answer & Propolis Autopsy
Correct Key: Option C Diagnostic Explanation
Concept: Commutative Property of Variable Sums.

Formula: \(A+B+C = C+B+A\)

Solution: Reordering letter variables leaves their numerical total invariant.

Why other options are incorrect:

• Options A, B, and D: Disregard the basic algebraic principle that changing variable order does not alter sum.
#4 of 11 BUMHS 2025
Permalink
What would be the result of: \(10 - 3 \times 2\)?
A
4
B
6
C
14
D
17
View Answer & Propolis Autopsy
Correct Key: Option A Diagnostic Explanation
Concept: Order of Operations.

Formula: Multiplication before subtraction.

Solution:

  • \(10 - (3 \times 2) = 10 - 6 = 4\).


Why other options are incorrect:

• Option C: Evaluates left-to-right: \((10 - 3) \times 2 = 14\).
#5 of 11 SZABMU 2025
Permalink
Every alphabet in the word "SURGEON" represent a fixed numerical value and the numbers when added, sum up to 99. Based on this, what will be the sum of the word "EORGNSU".
A
102
B
78
C
99
D
56
View Answer & Propolis Autopsy
Correct Key: Option C Diagnostic Explanation
Concept: Anagram Sum Equivalence.

Formula: N/A

Solution: Identical letters maintain an identical total sum of 99.

Why other options are incorrect:

• Options A, B, and D: Violate fixed variable algebraic sum rules.
#6 of 11 DUHS 2024
Permalink
Which number is a multiple of its digits?
A
21
B
47
C
52
D
24
View Answer & Propolis Autopsy
Correct Key: Option D Diagnostic Explanation
Concept: Divisibility & Digit Product Rules.

Formula: \(N \pmod{d_1 \times d_2} = 0\)

Solution: Digits of 24 are 2 and 4. Product = \(2 \times 4 = 8\). Since \(24 / 8 = 3\), 24 is a multiple of its digits' product.

Why other options are incorrect:

• Option A: Digits product = 2; 21 is odd (not divisible by 2).
#7 of 11 UHS 2024
Permalink
P, Q and R are one-digit, non-negative numbers. P is the smallest even number. Q is the largest odd number. R is 5.

Which of the following is true?
A
P + Q + R = 16
B
P + Q + R = 12
C
(Q + R) × P = 30
D
(Q + R) × P = 8
View Answer & Propolis Autopsy
Correct Key: Option A Diagnostic Explanation
Concept: Number Property Evaluation.

Formula: \(P = 2, Q = 9, R = 5\)

Solution:

  • Smallest positive single-digit even number \(P = 2\).


  • Largest single-digit odd number \(Q = 9\).


  • \(P + Q + R = 2 + 9 + 5 = 16\).


Why other options are incorrect:

• Option C: Calculates \((9 + 5) \times 2 = 28\) (not 30).
#8 of 11 UHS 2024
Permalink
X, Y and Z are three whole numbers less than 24 but greater than 11. X is the smallest prime number in this range. Y is the largest number divisible by 3. Z is the smallest number divisible by 11.
A
X is 13, Y is 24, Z is 11
B
X is 13, Y is 21, Z is 22
C
X is 11, Y is 21, Z is 11
D
X is 11, Y is 24, Z is 22
View Answer & Propolis Autopsy
Correct Key: Option B Diagnostic Explanation
Concept: Number Bounds & Factors.

Formula: Bounds = \(12 \le N \le 23\).

Solution:

  • Smallest prime in range = 13 (\(X\)).


  • Largest multiple of 3 in range = 21 (\(Y\)).


  • Smallest multiple of 11 in range = 22 (\(Z\)).


Why other options are incorrect:

• Option A: Includes 24 and 11 which violate strictly 'less than 24 and greater than 11'.
#9 of 11 UHS 2023
Permalink
X, Y and Z are three whole numbers less than 31 but greater than 23. X is a prime number. Y is the largest odd number smaller than 35. Z is the smallest even number?
A
X is 31, Y is 29 and Z is 24
B
X is 29, Y is 29 and Z is 24
C
X is 23, Y is 29 and Z is 24
D
X is 27, Y is 31 and Z is 26
View Answer & Propolis Autopsy
Correct Key: Option B Diagnostic Explanation
Concept: Bounded Interval Whole Numbers.

Formula: Interval = \((23, 31)\).

Solution: Prime = 29 (X), Max odd < 35 in range = 29 (Y), Min even = 24 (Z).

Why other options are incorrect:

• Option A: Includes interval boundary 31.
#10 of 11 BUMHS 2022
Permalink
X, Y and Z are three whole numbers less than 31 but greater than 23. X is a prime number. Y is the largest odd number smaller than 35. Z is the smallest even number.
A
X is 31, Y is 29 and Z is 24
B
X is 29, Y is 29 and Z is 24
C
X is 23, Y is 29 and Z is 24
D
X is 27, Y is 31 and Z is 26
View Answer & Propolis Autopsy
Correct Key: Option B Diagnostic Explanation
Concept: Whole Number Sets.

Formula: Interval = \((23, 31)\).

Solution: Prime = 29, Max odd = 29, Min even = 24.

Why other options are incorrect:

• Option A: Includes upper boundary 31.
#11 of 11 SZABMU 2022
Permalink
X, Y and Z are three whole numbers less than 24 but greater than 11. X is the smallest prime number. Y is the largest number divisible by 3. Z is the smallest number divisible by 11.
A
X is 13, Y is 24, Z is 11
B
X is 13, Y is 21, Z is 22
C
X is 11, Y is 21, Z is 11
D
X is 11, Y is 24, Z is 22
View Answer & Propolis Autopsy
Correct Key: Option B Diagnostic Explanation
Concept: Integer Interval Bounds.

Formula: Interval = \((11, 24)\).

Solution: Smallest prime = 13 (X), Largest multiple of 3 = 21 (Y), Smallest multiple of 11 = 22 (Z).

Why other options are incorrect:

• Option A: Includes boundary values 24 and 11.
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