Physics Dawn of Modern Physics ETEA 2014
PMDC Verified Question 52 of 52
Select the correct relation between wave and particle nature of radiation?
A
\( E = \frac{\lambda c}{h} \)
B
\( E = \frac{hc}{\lambda} \)
C
\( E = \frac{hc}{c} \)
D
\( E = h \lambda c \)
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option B: \( E = \frac{hc}{\lambda} \)
Concept:

The dual nature of radiation (wave-particle duality) bridges a photon's energy (particle property) with its wavelength (wave property).

Formula:

$$ E = hf \quad \text{and} \quad c = f\lambda $$

Solution:

  • Substitute \( f = \frac{c}{\lambda} \) into Planck's energy equation.


  • This yields \( E = \frac{hc}{\lambda} \).


Why other options are incorrect:

The other options have algebraically incorrect arrangements of Planck's constant, the speed of light, and wavelength, resulting in incorrect dimensional units for energy.

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