Concept:A full-wave rectifier converts both the positive and negative halves of each input AC cycle into positive output pulses. Thus, for every complete input cycle, two output pulses are generated, doubling the ripple frequency.
Formula:$$f_{\text{ripple, FW}} = 2 f_{\text{in}}$$
$$\text{whereas } f_{\text{ripple, HW}} = f_{\text{in}}$$
Solution:- Given input AC frequency: \(f_{\text{in}} = 50\text{ Hz}\).
- For a full-wave rectifier:
- $$f_{\text{ripple}} = 2 \times 50\text{ Hz} = 100\text{ Hz}$$
Why other options are incorrect:- Option A: \(25\text{ Hz}\) would imply halving the frequency, which does not occur in rectification.
- Option B: \(50\text{ Hz}\) is the ripple frequency for a half-wave rectifier (\(f_{\text{ripple}} = f_{\text{in}}\)).
- Option D: \(200\text{ Hz}\) corresponds to a quadrupled frequency, which is not produced by standard single-phase full-wave circuits.
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