Physics Electronics PMDC Conceptual Practice
PMDC Verified Question 12 of 494
When a reverse bias voltage is applied across a \(\text{p-n}\) junction diode, the magnitude of the small reverse current that flows is determined primarily by:
A
The concentration of majority carriers in the doped regions
B
The rate of thermal generation of minority electron-hole pairs
C
The cross-sectional area of the external connecting wires
D
The magnitude of the applied reverse voltage over a wide range
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option B: The rate of thermal generation of minority electron-hole pairs
Concept:

Under reverse bias, the electric field at the junction sweeps thermally generated minority carriers across the depletion layer. Because the minority carrier concentration depends almost entirely on temperature and intrinsic thermal generation, the reverse saturation current is largely independent of applied voltage (until breakdown).

Formula:

$$I_s \propto T^3 e^{-\frac{E_g}{k_B T}}$$

Solution:

  • Reverse current is caused by minority electrons in the p-side and minority holes in the n-side.


  • These minority carriers are produced by thermal breaking of covalent bonds.


  • Consequently, this reverse current depends strongly on temperature rather than the applied reverse voltage.


Why other options are incorrect:

  • Option A: Majority carriers are blocked by the heightened potential barrier in reverse bias.
  • Option C: Connecting wire geometry has negligible influence on junction leakage current.
  • Option D: Once reverse saturation is reached, increasing the reverse voltage does not noticeably increase current until breakdown.

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