Physics Electronics PMDC Conceptual Practice
PMDC Verified Question 135 of 494
Under normal operating conditions, a Zener diode is designed to operate primarily in which region of its characteristic I-V curve?
A
Forward-bias knee region
B
Unbiased equilibrium region
C
Reverse-bias breakdown region
D
Deep reverse cut-off region below breakdown
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option C: Reverse-bias breakdown region
Concept:

A Zener diode is designed to operate in reverse breakdown, where its terminal voltage remains virtually constant at \( V_Z \) over a wide range of reverse currents, making it ideal for voltage regulation.

Formula:

$$V_{\text{out}} = V_Z = \text{constant} \quad (\text{for } I_{Z,\text{min}} < I_Z < I_{Z,\text{max}})$$

Solution:

  • In reverse breakdown, the slope of the I-V curve is nearly vertical (very low dynamic impedance \( r_z \)).


  • This allows the Zener diode to maintain a stable reference voltage despite fluctuations in supply voltage or load current.


Why other options are incorrect:

  • Option A: In forward bias, a Zener diode behaves like an ordinary silicon diode (\( V_F \approx 0.7\text{ V} \)) without voltage regulation.
  • Option B: In an unbiased state, the diode does not conduct or regulate voltage.
  • Option D: Below breakdown, the diode only passes a tiny leakage current and cannot regulate voltage.

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