Physics Electronics PMDC Conceptual Practice
PMDC Verified Question 172 of 494
What is the average DC voltage delivered to a load resistor by a full-wave bridge rectifier with a peak output voltage of \( V_m = 314\text{ V} \)?
A
200 V
B
100 V
C
157 V
D
222 V
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option A: 200 V
Concept:

The average (DC) value of a full-wave rectified sine wave is given by \( V_{\text{dc}} = \frac{2V_m}{\pi} \).

Formula:

$$V_{\text{dc}} = \frac{2 V_m}{\pi}$$

Solution:

  • Given: \( V_m = 314\text{ V} \approx 100\pi\text{ V} \).


  • \( V_{\text{dc}} = \frac{2 \times 314}{\pi} = \frac{628}{3.14} = 200\text{ V} \).


Why other options are incorrect:

  • Option B: 100 V is the DC output of a half-wave rectifier (\( V_m / \pi \)).
  • Option C: 157 V is half the peak voltage (\( V_m / 2 \)), which is the RMS value of a half-wave rectifier.
  • Option D: 222 V is the RMS value of this full-wave output (\( 314 / \sqrt{2} \approx 222\text{ V} \)).

Quality & Fidelity Assurance: Every question on BeambePrep is rigorously curated against the official PMDC syllabus with zero filler, zero out-of-syllabus content, and zero typos. When an authentic past paper originally contained a historical mistake or ambiguity from the examining board (such as UHS or NUMS), BeambePrep faithfully reflects the original paper while detailing the nuance and scientific consensus in the autopsy above.

Previous Question All Electronics MCQs Next Question

Want to solve full-length papers under timed exam conditions?

Practice with zero-scroll lockdown sprints, dynamic latency zone timers, live peer selection telemetry, and the automated Amber mistake recovery loop.

Enter Arena Sprint iOS App Android App