Physics Electronics PMDC Conceptual Practice
PMDC Verified Question 173 of 494
For a half-wave rectifier with a peak output voltage \( V_m = 314\text{ V} \), the average DC output voltage across the load resistor is:
A
50 V
B
100 V
C
200 V
D
157 V
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option B: 100 V
Concept:

The average (DC) value of a half-wave rectified waveform is given by \( V_{\text{dc}} = \frac{V_m}{\pi} \).

Formula:

$$V_{\text{dc}} = \frac{V_m}{\pi}$$

Solution:

  • Given: \( V_m = 314\text{ V} \approx 100\pi\text{ V} \).


  • \( V_{\text{dc}} = \frac{314}{3.14} = 100\text{ V} \).


Why other options are incorrect:

  • Option A: 50 V is half the correct DC value.
  • Option C: 200 V is the DC output of a full-wave rectifier (\( 2V_m / \pi \)).
  • Option D: 157 V is the RMS value of the half-wave output (\( V_m / 2 \)).

Quality & Fidelity Assurance: Every question on BeambePrep is rigorously curated against the official PMDC syllabus with zero filler, zero out-of-syllabus content, and zero typos. When an authentic past paper originally contained a historical mistake or ambiguity from the examining board (such as UHS or NUMS), BeambePrep faithfully reflects the original paper while detailing the nuance and scientific consensus in the autopsy above.

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