Physics Electronics PMDC Conceptual Practice
PMDC Verified Question 175 of 494
A sinusoidal AC voltage with a peak value of \( V_m = 100\text{ V} \) appears across each half of a center-tapped transformer winding feeding a full-wave rectifier. What is the Peak Inverse Voltage (PIV) rating required for each diode?
A
50 V
B
70.7 V
C
100 V
D
200 V
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option D: 200 V
Concept:

In a center-tapped full-wave rectifier, each non-conducting diode must withstand twice the peak half-winding voltage (\( 2V_m \)).

Formula:

$$\text{PIV}_{\text{center-tapped}} = 2 V_m$$

Solution:

  • Given: Peak half-winding voltage \( V_m = 100\text{ V} \).


  • When one diode conducts at peak voltage, the other diode experiences a reverse voltage of \( \text{PIV} = 2V_m = 2 \times 100\text{ V} = 200\text{ V} \).


Why other options are incorrect:

  • Option A: 50 V is far below the required PIV rating.
  • Option B: 70.7 V represents the RMS voltage of a single half-winding.
  • Option C: 100 V is the PIV for a bridge rectifier, but is insufficient for a center-tapped circuit.

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