Physics Electronics PMDC Conceptual Practice
PMDC Verified Question 174 of 494
A sinusoidal AC voltage with a peak value of \( V_m = 100\text{ V} \) is applied across the secondary winding of a transformer feeding a bridge rectifier. What is the Peak Inverse Voltage (PIV) rating required for each diode?
A
200 V
B
50 V
C
100 V
D
70.7 V
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option C: 100 V
Concept:

In a bridge rectifier, the maximum reverse voltage across each non-conducting diode equals the peak secondary voltage \( V_m \).

Formula:

$$\text{PIV}_{\text{bridge}} = V_m$$

Solution:

  • Given: \( V_m = 100\text{ V} \).


  • Each non-conducting diode must withstand a peak reverse voltage of \( \text{PIV} = V_m = 100\text{ V} \).


Why other options are incorrect:

  • Option A: 200 V is the PIV required in a center-tapped full-wave rectifier (\( 2V_m \)).
  • Option B: 50 V is below the peak reverse voltage and would cause breakdown.
  • Option D: 70.7 V is the RMS value (\( 100 / \sqrt{2} \)), not the peak reverse voltage.

Quality & Fidelity Assurance: Every question on BeambePrep is rigorously curated against the official PMDC syllabus with zero filler, zero out-of-syllabus content, and zero typos. When an authentic past paper originally contained a historical mistake or ambiguity from the examining board (such as UHS or NUMS), BeambePrep faithfully reflects the original paper while detailing the nuance and scientific consensus in the autopsy above.

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