Concept:Extract the input frequency from the angular frequency \( \omega = 2\pi f_{\text{in}} \), then double it to find the full-wave ripple frequency: \( f_{\text{ripple}} = 2 f_{\text{in}} \).
Formula:$$\omega = 100\pi\text{ rad/s} \implies f_{\text{in}} = \frac{\omega}{2\pi} = \frac{100\pi}{2\pi} = 50\text{ Hz}$$
$$f_{\text{ripple}} = 2 \times f_{\text{in}} = 2 \times 50\text{ Hz} = 100\text{ Hz}$$
Solution:- The input angular frequency is \( \omega = 100\pi \), giving an input frequency of \( f_{\text{in}} = 50\text{ Hz} \).
- Because a full-wave rectifier produces two pulses per cycle, the output ripple frequency is \( 2 \times 50\text{ Hz} = 100\text{ Hz} \).
Why other options are incorrect:- Option A: 50 Hz is the input mains frequency.
- Option C: 200 Hz would require an input frequency of 100 Hz.
- Option D: 25 Hz would imply sub-harmonic division.
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