Concept:Short-circuit current \( I_{\text{sc}} \) is directly proportional to the photon absorption rate (light intensity), while open-circuit voltage \( V_{\text{oc}} \) depends logarithmically on the ratio of photo-current to dark saturation current.
Formula:$$I_{\text{sc}} \approx I_L \propto \Phi$$
$$V_{\text{oc}} = \frac{k T}{q} \ln\left(\frac{I_{\text{sc}}}{I_0} + 1\right) \propto \ln(\Phi)$$
Solution:- Increasing light intensity generates more electron-hole pairs per second, causing \( I_{\text{sc}} \) to increase linearly with \( \Phi \).
- Because \( V_{\text{oc}} \) is logarithmic in \( I_{\text{sc}} / I_0 \), it rises quickly at low light levels and then flattens out, saturating near the built-in barrier potential.
Why other options are incorrect:- Option A: \( V_{\text{oc}} \) increases logarithmically, not linearly.
- Option C: \( I_{\text{sc}} \) increases with illumination rather than remaining constant.
- Option D: Both parameters increase with higher light intensity.
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