Concept:Series resistance \( R_s \) causes internal \( I R \) voltage drops under load current, flattening the knee of the I-V curve, reducing the Fill Factor (\( \text{FF} \)), and lowering peak power output \( P_{\text{max}} \).
Formula:$$V_{\text{terminal}} = V_{\text{junction}} - I R_s \implies \text{Fill Factor } \text{FF} \downarrow \implies P_{\text{max}} = \text{FF} \cdot V_{\text{oc}} \cdot I_{\text{sc}} \downarrow$$
Solution:- At open circuit (\( I = 0 \)), no current flows through \( R_s \), so \( V_{\text{oc}} \) remains unchanged.
- Under load, current flowing through \( R_s \) reduces the terminal voltage, rounding the I-V curve and lowering the Fill Factor and maximum power output.
Why other options are incorrect:- Option A: \( R_s \) does not increase \( V_{\text{oc}} \); at \( I = 0 \), \( V_{\text{oc}} \) is unchanged.
- Option B: Series resistance increases resistive losses and does not stop recombination.
- Option D: Solar cells generate DC power, not AC.
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