Chemistry Stoichiometry MDCAT 2017
PMDC Verified Question 87 of 105
Which one of the followings has same number of molecules as present in 11g of \( \text{CO}_2 \)?
A
4g of \( \text{O}_2 \)
B
4g of O
C
4.5 g of \( \text{H}_2\text{O} \)
D
¼ moles of NaCl
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option C: 4.5 g of \( \text{H}_2\text{O} \)
Concept:

According to Avogadro's hypothesis, samples of different molecular substances will contain the same number of molecules if they possess the exact same number of moles.

Formula:

$$ \text{Moles} (n) = \frac{\text{Mass}}{\text{Molar Mass}} $$

Solution:

  • First, find the moles of the reference substance (\( \text{CO}_2 \)):


  • \( n_{\text{CO}_2} = 11 \text{ g} / 44 \text{ g/mol} = 0.25 \text{ moles} \) (or 1/4 mole).


  • Now evaluate the correct option (C) \( \text{H}_2\text{O} \):


  • \( n_{\text{H}_2\text{O}} = 4.5 \text{ g} / 18 \text{ g/mol} = 0.25 \text{ moles} \) (or 1/4 mole).


  • Since both equate to 0.25 moles, they contain identical numbers of molecules.


Why other options are incorrect:

  • 4g of \( \text{O}_2 \): \( 4/32 = 0.125 \text{ moles} \).


  • 4g of O: \( 4/16 = 0.25 \text{ moles} \), BUT Oxygen atoms are not molecules. The question specifically asks for "number of molecules".


  • ¼ moles of NaCl: NaCl is an ionic compound and consists of "formula units", not molecules.

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